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Probability - Gravner-9

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Number of Permutations among Norwegians = $3!$

Number of Permutations among Swedes = $4!$

Number of Permutations among Finns= $5!$

Number of permutations among these 3 groups = $(3-1)! = 2$

Favorable permutations = $3! \  4! \  5!  \ 2!$

Probability = $\large \frac{3! \  4! \  5!  \ 2!}{(12-1)!}=  \frac{3! \  4! \  5!  \ 2!}{11!}$
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