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Consider an organization with a class-C IP network address of 195.37.5.0, they wish to divide the network into different sub networks. The subnet mask is 255.255.255.192
Q.1. Which one of the following is not a broadcast address in any of the sub network?
(A) 195.37.5.127 (B) 195.37.5.191 (C) 195.37.5.31 (D) 195.37.5.255

Q.2. The correct IP address belongs to
(A) The first sub network (B) The second sub network
(C) third sub network (D) Fourth sub network

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C
For a broadcast address, all the bits in the host id part should be 1 (in binary). Since the mask is 255.255.255.192. So, we have 6 bits as HID, 2 bits as SUBNET ID and 24 bits as NID.
195.37.5.31 : When we expand the last octet, it is 00011111
iN THE HID, WE HAVE 011111. SO IT IS NOT A BROADCAST ADDRESS. ITS IS A HOST ADDRESS.
IT SHOULD HAVE BEEN 195.37.5.63 i.e 00111111

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