0 votes 0 votes "Every cyclic K-map given cyclic function and every cyclic function can be the self-dual function." What is the meaning of cyclic K-map? Digital Logic k-map + – Shaik Masthan asked Sep 23, 2018 Shaik Masthan 426 views answer comment Share Follow See all 10 Comments See all 10 10 Comments reply srestha commented Sep 23, 2018 reply Follow Share this might be https://gateoverflow.in/173362/self-doubt is it important? 0 votes 0 votes Shaik Masthan commented Sep 23, 2018 reply Follow Share this might be https://gateoverflow.in/173362/self-doubt This is not sufficient. doubt came from the comment of the BEST answer https://gateoverflow.in/29414/identifying-self-dual-function 0 votes 0 votes srestha commented Sep 23, 2018 reply Follow Share ok but not getting much information about it , in internet 0 votes 0 votes Shubhgupta commented Sep 23, 2018 reply Follow Share every prime implicant which is covered by at least two prime implicant and there is no essential prime implicant present in k-map called as cyclic k-map. 0 votes 0 votes Shaik Masthan commented Sep 24, 2018 reply Follow Share 1) then there are more than 1 cyclic configuration of K-map https://gateoverflow.in/173362/self-doubt should have more than 2 possibilities 2) Is every self-dual function leads to cyclic k-map? otherwise it just " every cyclic k-map lead to self-dual " 0 votes 0 votes Shubhgupta commented Sep 24, 2018 reply Follow Share https://gateoverflow.in/173362/self-doubt should have more than 2 possibilities How? if you will solve above k-map with prime implicant table then you will get only two possibilities which is mentioned in above link. Is every self-dual function leads to cyclic k-map? otherwise it just " every cyclic k-map lead to self-dual " I don't know, how this can be true? Because in self dual function number of minterms should be equal to no. of maxterms. But this is not the case in cyclic function 0 votes 0 votes Shaik Masthan commented Sep 24, 2018 reply Follow Share How? if you will solve above k-map with prime implicant table then you will get only two possibilities which is mentioned in above link. I don't know, how this can be true? Because in self dual function number of minterms should be equal to no. of maxterms. But this is not the case in cyclic function then the given statement (in the question) should be false, right? 0 votes 0 votes Shubhgupta commented Sep 24, 2018 reply Follow Share your k-map(1,2,3,4,5,6) and mine(0,1,2,5,6,7(don't consider digit which is mentioned in k-map)) are totally different. And yes this statement should be wrong from my point of view. 0 votes 0 votes Shaik Masthan commented Sep 24, 2018 reply Follow Share in that question they didn't mention anything about minterms.. So, if you fix the minterms, then you have 2 possibilities. But fixing the minterms have more than 1 choice. 1 votes 1 votes Shubhgupta commented Sep 24, 2018 reply Follow Share yes @shaik I haven't checked that question previously but according to that question yes there are more than 2 possibilities. 0 votes 0 votes Please log in or register to add a comment.