0 votes 0 votes Let $X$ be a random variable with $P(X=1) =0.2,P(X=2)=0.3$, and $P(X=3)=0.5$. What is the expected value of $X$? Probability probability engineering-mathematics gravner random-variable + – Pooja Khatri asked Sep 25, 2018 Pooja Khatri 277 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
1 votes 1 votes E(X)= 0.2*1+0.3*2+0.5*3 E(X)-0.2 + 0.6 +1.5=2.3 Expected value of X is 2.3 Tesla! answered Sep 25, 2018 Tesla! comment Share Follow See all 0 reply Please log in or register to add a comment.