How to solve this equation ( general Mathematics equation) to find a value of a variable

Question

3*10^-8/0.8 = H(2*10^-8 + 10^-8) + (1-H) (10^-8 + 10^-3)

My Take so far - 

3*10^-8/0.8 = H(3*10^-8) + (1-H) (10^-11)

3*10^-8/0.8 = H(3*10^-8) + 10^-11 - 10^-11*H

Now I can't able to solve any further. 

What I tried more is I cancelled (3*10^-8) from both LHS and RHS and I got 

1/0.8 = H + (1-H)*10-11 /// ( I took 10^-11 common from 10^-11 - 10^-11*H)

So what to do after 1/0.8 = H + (1-H)*10-11

Comments

Brother the reason for cancel all 10-8 terms in the eqn or numerator?

Are all those 10^-8 are common terms in numerator that's why we cancel them?

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if all are in numerator ===> you can cancel them

if all are in denominator ===> you can cancel them

if some are in Numerator and some are in denominator ===> you can't cancel them

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Perfect thanks! :)