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GATE19942.8
+9
votes
512
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Let $A, B$ and $C$ be independent events which occur with probabilities $0.8, 0.5$ and $0.3$ respectively. The probability of occurrence of at least one of the event is _____
gate1994
probability
normal
numericalanswers
asked
Oct 4, 2014
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Kathleen
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2
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+14
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Best answer
$P(A) = 0.8$ $\implies$ $P(A') =$ $1  0.8 = 0.2$
$P(B) = 0.5$ $\implies$ $P(B')$ = $1  0.5 = 0.5$
$P(C) = 0.3$ $\implies$ $P(C')$ = $1  0.3 = 0.7$
$P$(No event will occur): =$ 0.2 * 0.5 * 0.7 = 0.07$
$P$(at least 1 event will occur): $1  0.07 = 0 .93$
answered
Oct 10, 2014
by
Manu Thakur
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edited
Jun 8, 2018
by
Milicevic3306
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+2
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P(at least A or B or C )= P(A u B u c)
= 0.8+0.5+0.3(0.8*0.5) (0.5 *0.3) (0.8*0.3)+(0.8*0.5*0.3)
=1.60.67
=0.93
answered
Jun 14, 2018
by
sutanay3
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3.8k
points)
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This is right but above method is fast.
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Answer:
0.93
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