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2 Answers

Best answer
34 votes
34 votes
$P(A) = 0.8 \implies P(A') = 1 - 0.8 = 0.2$

$P(B) = 0.5 \implies P(B') = 1 - 0.5 = 0.5$

$P(C) = 0.3 \implies P(C') = 1 -  0.3 = 0.7$

$P$ (No event will occur)$ = 0.2 \ast 0.5 \ast 0.7 = 0.07$

$P$ (at least $1$ event will occur)$ = 1 - 0.07 = 0 .93$
edited by
7 votes
7 votes
P(at least A or B or C )= P(A u B u c)

= 0.8+0.5+0.3-(0.8*0.5) -(0.5 *0.3) -(0.8*0.3)+(0.8*0.5*0.3)

=1.6-0.67

=0.93
Answer:

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