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asked in Digital Logic by Loyal (6.6k points) | 50 views
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My answer :-

Given POS if i take complement of the function then i will get SOP ==> Duality + complementing the literals

Hence = A'B'C + A'BC + AB'C' + ABC            

Am i right ? but given answer is B what's wrong in my concept please clear me out ?
+2
B is correct. $\prod (1,3,4,7)$

then SOP = $\sum (0,2,5,6)$ = $A'B'C' + AB'C + A'BC' + ABC'$
0
brother what is wrong in my approach am i applying something wrong ?
0

Na462 i follow the K-Map method, but by your method it is coming out to be the SOP of complement of the given function

0
But brother the complement of SOP = POS right to usse bhi to right aana chahiye na ?
0
SOP = POS because they are just the representation of the same function
+1
apply DeMorgans on the given function 2 times you'll get SOP
0
i got it now :)

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