The Gateway to Computer Science Excellence
First time here? Checkout the FAQ!
0 votes

Tanenbaum connection establishment 

asked in Computer Networks by (209 points) | 232 views

2 Answers

+1 vote

Part 1)

The 15 bit wide clock counter can produce 215 sequence numbers, producing 1 every 100 milliseconds. (1 msec = 10-3 sec)

$\Rightarrow$ 1 sequence number is produced in 100 x 10-3 sec,

$\Rightarrow$ 215 sequence numbers can be produced in 215 x 100 x 10-3 seconds = 3276.8 sec $\Rightarrow$ 54.61 minutes.

As the sequence numbers will start repeating after the expiry of lifetime (which is given as 60 sec, we dont have any issue)

Part 2)

240 sequence numbers in 60 sec,

$\Rightarrow$ 1 sequence number in $\Rightarrow \frac{60}{240}$ sec

$\Rightarrow$ 215 sequence numbers in $\Rightarrow \frac{60}{240} \times 2^{15}$ = 8192 sec $\Rightarrow$ 136.53 minutes

answered by Active (4k points)
0 votes
i think this should be the answer

15 bit counter can count 2^15 sequence numbers . so total sequence number will be 2^15. total time to blow up all sequence number =100msec*2^15

=3276.800 seconds (worst case) we have to reset the counter. well as life time of packet is far less than the time to reset counter no issue will occur .


if we use 240 sequence number per minute then.

total time to eat up all sequence number will be

2^15/240=136.5 minutes =137 minutes
answered by Boss (15.9k points)

Quick search syntax
tags tag:apple
author user:martin
title title:apple
content content:apple
exclude -tag:apple
force match +apple
views views:100
score score:10
answers answers:2
is accepted isaccepted:true
is closed isclosed:true

39,513 questions
46,665 answers
57,486 users