1 votes 1 votes Digital Logic digital-logic k-map prime-implicants minimization + – Na462 asked Oct 1, 2018 Na462 1.5k views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Magma commented Oct 1, 2018 reply Follow Share 5 prime implicants 2 essential Prime Implicants 0 votes 0 votes Na462 commented Oct 1, 2018 reply Follow Share I got 2 right but please explain why 5 why not 4 ? are you counting all the possible prime implicants possible or you're simply solving the question by simply making pairs and then counting 0 votes 0 votes Magma commented Oct 1, 2018 reply Follow Share here 5 prime implicants and I and V are essential prime implicants 0 votes 0 votes Na462 commented Oct 1, 2018 reply Follow Share Magma why you're making 2nd prime implicant when all 1s of 1st and 2nd pairs are grouped ? 0 votes 0 votes Swapnil Naik commented Oct 1, 2018 reply Follow Share because we need to consider all combination of pairs. some additional info that I found very helpful: Prime implicants all possible combinations of minterms with preference from oct then quad then pair. eg. if quad possible then don't try internal pair and assume they are also prime implicants Essential prime implicants: There is at least a one min term in octet,quad,pair which is not covered by any other prime implicant. useful question: https://gateoverflow.in/204124/gate2018-49 good tutorial: https://www.youtube.com/watch?v=SyTGG2TeJJw Useful reference: https://www.geeksforgeeks.org/digital-logic-implicants-k-map/ 0 votes 0 votes Mk1234 commented Dec 14, 2022 reply Follow Share Option d is correct 5 prime . I and 2 EPI 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes Using K-map, 5 Prime Implicants And 2 Essential Prime Implicants Answer is Option C Devwritt answered Oct 4, 2018 Devwritt comment Share Follow See all 0 reply Please log in or register to add a comment.