0 votes 0 votes Shankar Kakde asked Oct 1, 2018 Shankar Kakde 260 views answer comment Share Follow See all 4 Comments See all 4 4 Comments reply Magma commented Oct 1, 2018 reply Follow Share 20% ?? 0 votes 0 votes Shankar Kakde commented Oct 2, 2018 reply Follow Share yes, How you got it?? 0 votes 0 votes Magma commented Oct 2, 2018 reply Follow Share find the efficiency = $\frac{1}{1+2a}$ a = propagation delay / transmission delay propagation delay = Tp = 20 $\mu s$ Transmission delay = L /B sec L = 5000 bits B = 500 x 10 6 bits per second a = (20 x 10 -6 * 500 * 10 6)/ 5000 a = 2 efficiency = 1 / 1 + 2*2 = 1/5 = 0.2 = 20% 1 votes 1 votes minal commented Oct 2, 2018 reply Follow Share in answer they gave any range ? 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes 20% L=5000bits B=500Mbps Tx=10 microsec. a=Tp/Tx efficiency=1/(1+2a) =20% Kalpataru Bose answered Oct 2, 2018 Kalpataru Bose comment Share Follow See all 0 reply Please log in or register to add a comment.
