3 votes 3 votes a bit stuffing based framing protocol uses an 8bit delimiter pattern of HDLC's flag .if the input bit string is 1011111110111110,then the output bit string after after stuffing is Computer Networks bit-stuffing + – Gurdeep Saini asked Oct 3, 2018 • edited Jan 17, 2019 by Gurdeep Saini Gurdeep Saini 919 views answer comment Share Follow See 1 comment See all 1 1 comment reply gauravkc commented Oct 3, 2018 reply Follow Share The 8-bit delimiter pattern is 01111110 While sending data, to avoid getting it confused with delimiter pattern, a 0 is stuffed by sender when 5 consecutive 1's are encountered in data. Receiver ignores the 0 after 5 1's while parsing data. Hence the answer. 0 votes 0 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes Hdlc uses 7E (01111110) as a delimiter pattern. So to encode 1011111110111110 it will add a 0 after every 5 ones. So answer is 1011111'0'11011111'0'0 Here '0' is the stuffed bit. shreejeetp answered Oct 3, 2018 • selected Oct 3, 2018 by Gurdeep Saini shreejeetp comment Share Follow See all 4 Comments See all 4 4 Comments reply Gurdeep Saini commented Oct 3, 2018 reply Follow Share you said that hdlc use 7E delimiter , you have studied it or there is a method to find delimiter pattern 0 votes 0 votes shreejeetp commented Oct 3, 2018 reply Follow Share Its a standard. 1 votes 1 votes Rajesh Panwar commented Jan 25, 2019 reply Follow Share is it rule adding 0 after every occurrences of 1s. 0 votes 0 votes Gurdeep Saini commented Jan 25, 2019 reply Follow Share yes 0 votes 0 votes Please log in or register to add a comment.