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2 Answers

2 votes
2 votes
I think answer is D.It is very nice qs.6 is running and its next pointer is poiniting to 0.which is poiniting to in 3 ready.In 3 ready  next pointer is 12,which is pointing to 12 ready,in 12 ready next pointer 14,so pointing to 14 ready,then pointing to 6 ready,and lastly next pointer * pointing to free 8...

pls let me know if I am correct or not..and als what is the answer.
1 votes
1 votes
I think option B is the answer because in running header 6 is the current one and 0 is the pointer to next .In 0 ready,3 is the next.In 3 ready 12 is the next.In 12 ready,14 is the next.In 14 ready 6 is the next.

Please correct me if am wrong.

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