I think answer is D.It is very nice qs.6 is running and its next pointer is poiniting to 0.which is poiniting to in 3 ready.In 3 ready next pointer is 12,which is pointing to 12 ready,in 12 ready next pointer 14,so pointing to 14 ready,then pointing to 6 ready,and lastly next pointer * pointing to free 8...
pls let me know if I am correct or not..and als what is the answer.