1 votes 1 votes Digital Logic test-series + – Prince Sindhiya asked Oct 6, 2018 • edited Oct 6, 2018 by Prince Sindhiya Prince Sindhiya 338 views answer comment Share Follow See all 3 Comments See all 3 3 Comments reply Shaik Masthan commented Oct 7, 2018 reply Follow Share check this https://gateoverflow.in/11625/plz-explain https://gateoverflow.in/244915/mod-n-counter in the question, it should be lowest MOD-N asynchronous counter 0 votes 0 votes Dharmendra Lodhi commented Oct 7, 2018 i moved by Dharmendra Lodhi Oct 7, 2018 reply Follow Share Tclk=100ns number of FF = 10 so MOD-1024 0 votes 0 votes Prince Sindhiya commented Oct 7, 2018 reply Follow Share @dharmendra i marked the 10 as it's answer because i thought it is not natural counter ( n bit then , mod 2^n) I thought that when we use the preset and clear concept then generally (n!=2^n) So, it should be mod-n counter Please clear my doubt that we should always take same case in these type of questions ( for natural counter) that is for n bit mod2^n ? One more thing i am not getting an insight feel of the question ( still Operating at 10MHz means )what this lines exactly want to say ? 0 votes 0 votes Please log in or register to add a comment.