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This schedule is:

A) Recoverable and conflict serializable
B) Irrecoverable and conflict serializable
C) Recoverable and non-conflict serializable
D) Irrecoverable and non-conflict serializable

 

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Its option D

Because Dirty Read exist (W(x) --> R(x)) in T3 --> T4, So Its non-recoverable.

 S: W3(x) W2(x) R4(x) W1(x) R3(x)

For this schedule through conflicts in precedence graph cycle exist ,So its not conflict serizable.

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