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What is the smallest number that when divided by 12, leaves 10, when divided by 16, leaves 14 and when divided by 24, leaves 22 as a remainder?

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The answer is as follows:-

Method goes as follows:-

The LCM of 12,16 and 24 is 48. Now on a common observation it is found that 12-10=2,16-14=2 and 24-22=2. So in a way the divisors are n+2 than the remainder. The common divisor. Therefore the least number will be 48-2=46. This is how the ans is reached.

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