1 votes 1 votes What is the smallest number that when divided by 12, leaves 10, when divided by 16, leaves 14 and when divided by 24, leaves 22 as a remainder? Quantitative Aptitude quantitative-aptitude general-aptitude general-topic-doubt + – Devshree Dubey asked Oct 9, 2018 edited Mar 9, 2019 by Abdul Wazeed Devshree Dubey 576 views answer comment Share Follow See all 5 Comments See all 5 5 Comments reply Show 2 previous comments Devshree Dubey commented Oct 9, 2018 reply Follow Share @Deepanshu,@Shaijal Tripathi,Both of you please work out the steps. 0 votes 0 votes Devshree Dubey commented Oct 9, 2018 reply Follow Share @If I m not wrong by adding the remainders 10,14 and 22 we get 46 as as the answer. Also, the LCM of the numbers is 48. The no 2 has to be subtracted from it. Is it the right way that I m approaching? 0 votes 0 votes Deepanshu commented Oct 9, 2018 reply Follow Share I JUST DID IT BY HIT AND RUN SO I AM NOT GOOD TO ANSWER THIS . : ) 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes The answer is as follows:- Method goes as follows:- The LCM of 12,16 and 24 is 48. Now on a common observation it is found that 12-10=2,16-14=2 and 24-22=2. So in a way the divisors are n+2 than the remainder. The common divisor. Therefore the least number will be 48-2=46. This is how the ans is reached. Devshree Dubey answered Oct 9, 2018 Devshree Dubey comment Share Follow See 1 comment See all 1 1 comment reply Shaijal Tripathi commented Oct 10, 2018 reply Follow Share Yes, just like you've done :) 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes This is how I solved it. Shaijal Tripathi answered Oct 10, 2018 Shaijal Tripathi comment Share Follow See all 0 reply Please log in or register to add a comment.