Number of 1 address instructions

Question

How many maximum number of one address instructions possible?

Comments

128????

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Yes, Even I got 128

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how u got 128??

I got 192

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@srestha

total no. of unused instructions will be 2^4-14=2

no this will be used in one address instruction so total no of 1 address instructions will be 2*2^6=2^7=128 since 6 bits more will be included in addition to given opcode as a new opcode for 1 address instruction

Answer 1

128 is the correct answer.

maximum 2 address instructions possible = 2^4 = 16,

but only 14 double address instructions used, so 16-14 = 2 double address instructions remains. Now for next 6 bit, we can have 2^6 = 64 combinations

=>2*64 = 128 comb for one address instructions.

So,answer is 128 only.

Answer 2

Total number of instruction = 2^4=16

Now 14 Double address instruction is there so left instructions =16-14 =2

then maximum number of 1 address instruction 2(2^6)+1*2^6=192.