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I think in this question no of Two addrees instruction also given . If that was given 14 then

answer will be 64 . Correct ?
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Total number of instructions possible = 2^4=16

Let x number of 2 Address instructions then

maximum 1 address instruction will be (16-x)*2^6 = 127 then x will be (1024-127)/64= 14.015.
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If no two address instruction allowed then, maximum of 57,408 zero address instructions allowed??

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