Stack

Question

the o/p of following program is:

queue Q=new queue();

stack S=new stack();

s.push(new interger(8));

s.push(new interger(9));

s.push(new interger(10));

q.enqueue(s.pop());

q.enqueue(new interger(8));

q.enqueue(new intergr(9));

s.push(q.dequeue());

system.out.print(s.pop());

system.out.print(s.pop());

a.10,8,9

b.8,9,10

c.9,8,10

d.10,9,8

my doubt is pf statemnt is 2 so why ans is giving in 3 val??

plx explain last 3 lines.i think in stack the element are 10,9,8 in pop out order(order in which they r pop out)

so ans is D???

Comments

There are only 2 print statements right? How are you getting 3 results?

---

yeah right

But if we pop 2 times it's 10  9

and if we pop 3 times it's 10 9  8

Answer 1

Yes U r thinking correct.

This question lacks none of the above option ;p

After doing all above specified operations.

Stack content(bottom to top):-8,9,10

 Queue Content :- 8,9

So then 2 consecutive pop operation will output 10,9 .