i think 49 will be the answer
three condition should be follow to choose key
(1) n=p*q=7*11
n=77
(2) Euler Totient function $\phi(n)=(p-1)(q-1)${if p and q are prime numbers}
$\phi(n) =6*10=60$
(3) now choose e such that 1<e<$\phi(n) $ and e and $\phi(n) $ should be coprime
means GCD(e,$\phi(n) $)=1
by seeing option only 49 is satisfying the condition because 49 is less than 60 and also GCD(49,60)=1
then (e,n) will be used as public key which will be used to encrypt the message .