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correct answer is 350 ..

We have to send a data of 4000 bytes

While MTU of given network is 1400 bytes and we know in the fragment offset we have the Scaling factor of 8 means,

In fragment offset we will have count oof how much 8 bytes of data is ahed of current one ..

So one I/P will have 1400/8=175 pieces of 8 Bytes ..

So 4000 bytes need  4000/8 = 500 pieces

to send 500 pieces we need 3 I/P packest as 500/175= 2.9

Now in last / 3rd packet we will have 175 + 175 (8 bytes pieces) = 350.

So fragment offset value is 350 for the last fragment.

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