1 votes 1 votes someone please explain option (C) and option (D)....... (ANSWER IS B). newdreamz a1-z0 asked Oct 15, 2018 newdreamz a1-z0 386 views answer comment Share Follow See all 7 Comments See all 7 7 Comments reply Show 4 previous comments Deepak Poonia commented Oct 15, 2018 reply Follow Share IF L1 IS REGULAR LANGUAGE AND L2 IS DCFL BUT NOT REGULAR THEN WHAT WILL BE (L1 INTERSECTION L2)? https://math.stackexchange.com/questions/1541057/dcfl-are-closed-under-intersection-with-regular-languages is ww^r CFL. If yes, how? $L = \left \{ ww^r | w \in \Sigma^+ \right \}$ is a context-free language $S \rightarrow aSa | bSb | aa | bb$ $L = \left \{ ww^r | w \in \Sigma^* \right \}$ is a context-free language $S \rightarrow aSa | bSb | \in $ 1 votes 1 votes amitqy commented Oct 16, 2018 reply Follow Share yes it is CFL.How to draw its PDA? There is no center available. 0 votes 0 votes garimanand commented Oct 23, 2018 reply Follow Share in option C complement of WW^r which is CFL Acceptable by NPDA . and cfl does not closed under closed under complementation so why C is not answer C is also CSL but Not CFL 0 votes 0 votes Please log in or register to add a comment.