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Question

Number of addition performed by above code? Please explain this?

Comments

8000+8000+4000=20000 times?

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But the answer is 28420 in the test series

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Oops..

 for i++,j++,k++ =20*20*20=8000

4000 times d=d+1

8000 times I+j+k, I.e., 16000 times +

So, total + operation= 8k+4k+16k= 28000 times

Where are those 420

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No. of additions : 20000

int main()

{

    int d =0,i,j,k;
    int count = 0;
    for(i=1;i<=20;i++)
    for(j=1;j<=20;j++)
    for(k=1;k<=20;k++)
    if((i+j+k)%2 ==0){
      d =d +1;
      count+=3;
    }
    else
    count+=2;
    printf("%d %d ",d,count);
   }