0 votes 0 votes F(A,B,C,D)=$\Sigma$(0,2,3,5,8,10,11,12,15) Realize it using 8:1 MUX . what is the logic behind? hitendra singh asked Oct 18, 2018 hitendra singh 797 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes Logic is we can make 8 x 1 MUX by using 4 variables, where select lines are 3 (S2, S1, S0) { S2 =A ,S1= B, S0 =C) D we can get from the inputs. Dharmendra Verma answered Oct 18, 2018 Dharmendra Verma comment Share Follow See all 14 Comments See all 14 14 Comments reply Show 11 previous comments akash.dinkar12 commented Oct 18, 2018 reply Follow Share whatever statement I have said earlier, that is true for general Here we are lucky in your example that we are able to implement 3 variable function with 22*1 MUX but what if we will provide C' at I0 and I3 inputs, then we can not implement it. here we are implementing 3 variable function with 4*1 MUX but we can not say that we can implement any 3 variable function with 4* 1 MUX 0 votes 0 votes hitendra singh commented Oct 18, 2018 reply Follow Share so we can't be sure right because in option it was given that few 3 variables functions are possible 0 votes 0 votes akash.dinkar12 commented Oct 18, 2018 reply Follow Share yes 0 votes 0 votes Please log in or register to add a comment.