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In IPv4 header, identification number field is 16 bits, and identification number is associated with each packet means you can

assign  unique ID number to 216 packets and each packet contains 2048 bytes of data.

So, You must transfer 216  *  2048 B of data within 10 sec.

So, Bandwidth =  (216 ∗ 2048 ∗ 8 bits) /  10 sec =  107.37 Mbps.

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