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Consider two Station communicating via 1 Mbps Satellite link with propagation delay of 270 msec. The Satellite merely serves to retransmit data received from one station to another,with negligible switch delay. If Ethernet frame size is 1024 bits with 3 bit sequence number,then max. possible data throughput is.................

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In the Above question, the maximum windows Size is 1+2a

if we are using the max sender windows size(stop and wait ARQ, GBN ARQ, Selective Repeat ARG)

windows Size of GBN is (using 3 sequence bit ) 7

than efficiency = 7/(1+2a)        (a= tp/tt )

tt =1024/1*10^6 = 1024 micro second 

a =270/1024=0.26

1+2a =0.26*2+1=1.52

efficiency =7/1.52  =4.6

 

 

 

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