Correct option: (E)
Angular diff. every min. b/w min. hand and hour hand = 5.5 degree
Initially, angular diff. b/w hour and min. hand = 0 degree
Suppose, after x min, angular diff. = 6 degree, (1/60 th of the circumference = (1/60) * 360 degree)
Therefore, angular distance covered in x min. = 6 degree
=> 5.5degree * x = 6 degree
=> x = (12/11) min
Also, the second hand is again exactly at zero after completing a full rotation , i.e. every minute.
Therefore, the conditions given in the question are satisfied after y min. such that
y = lcm((12/11), 1) min. = lcm(12, 11) min. = 132 min.