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Let arr[] be an array containing n integers. The following algorithm computes the frequency of each element in arr and stores it in another array fre[].

for(i=0;i<n;i++)
{

   count=1;
   for(j=i+1;j<n;j++)
   {  
         if(c)
          {  
             count++;
             fre[j]=0;
           }
    }
    if(fre[i]!=0)
     { 
        fre[i]=count;
      }
 }

Choose the correct expression for C

$A) arr[i]<=arr[j]$

$B) arr[i]>=arr[j]$

$C) arr[i]!=arr[j]$

$D) arr[i]==arr[j]$

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