Number of ways of choosing an Ace=$\binom{4}{1}$
Number of ways of choosing a King=$\binom{4}{1}$
Number of ways of choosing a Jack=$\binom{4}{1}$
the number of ways of choosing an Ace, a King and a Jack would be=$\binom{4}{1}$ *$\binom{4}{1}$ * $\binom{4}{1}$= 64
Number of ways of choosing 3 cards from a pack of 52 cards is = $\binom{52}{3}$ =22100
So the probability of drawing an Ace, a King and a Jack =$\frac{64}{22100}$ = $\frac{16}{5525}$
Hence (a) is the Answer.