0 votes 0 votes How many illegitimate states does synchronous mod-6 counter have? 1) 3 2) 2 3) 1 4) 0 Digital Logic tancet + – Balaji Jegan asked Oct 23, 2018 • edited Oct 23, 2018 by Balaji Jegan Balaji Jegan 1.4k views answer comment Share Follow See all 10 Comments See all 10 10 Comments reply Magma commented Oct 23, 2018 reply Follow Share how we defined the illegitimate states ?? I heard this term ist time can anyone explain me properly :3 0 votes 0 votes Hemanth_13 commented Oct 24, 2018 reply Follow Share What I felt after reading that word was the states which doesn't participate in counting loop are considered as illegitimate states. Its my assumption 0 votes 0 votes Magma commented Oct 24, 2018 reply Follow Share Hemanth_13 yes ...but answer given is 3 ..my doubt is how 3 states are illegitimate states here if we need mod 6 counter we need 3 flip flips [if we use Johnson counter] therefore total 8 states we have (0 to 7) In which states are required to make 6 mod counter remaining 2 are left therefore answer should be 2 right but I search in the Google ....and find correct answer is 3 if you find any solution for this or know how to solve this question let me know ok ??? 0 votes 0 votes Hemanth_13 commented Oct 24, 2018 reply Follow Share Magma Yes what you said was right in case of Johnson counter if we have n states we get mod 2n counter, so we have two illegitimate states. But we can use ring counter as well where we get mod n counter. Its huge taking to check with 6 bits 2^6=64 combinations I tried with 4 bits and i got 3 illegitimate states. 1 votes 1 votes Magma commented Oct 24, 2018 i edited by Magma Oct 24, 2018 reply Follow Share Hemanth_13 thanks !! you give the example of mod 4 for mod 6 also it gives 3 illegitimate states therefore it means In mod n counter using ring counter where n >= 3 and n is any arbitrary number gives 3 illegitimate states ?? 0 votes 0 votes Somoshree Datta 5 commented Oct 24, 2018 reply Follow Share But how to know which counter to consider?Its just said synchronous counter.. 0 votes 0 votes Magma commented Oct 24, 2018 reply Follow Share Hmm point ! but if it's given that it's a synchronous counter (ring counter) ..and mod n (n>=3) then it always gives 3 illegitimate states 0 votes 0 votes Hemanth_13 commented Oct 24, 2018 reply Follow Share Magma For n=3 we only get 2. Plz check once 0 votes 0 votes Magma commented Oct 24, 2018 reply Follow Share hmmm 2 :/ 0 votes 0 votes Balaji Jegan commented Oct 24, 2018 reply Follow Share Multiple Sources are saying are different answers. When I googled this question, answer was mentioned as 3 in 1 website, 1 in another website, 0 in another website. Now here in this website, you guys are saying 2 :\ 0 votes 0 votes Please log in or register to add a comment.