self doubt

Question

!

In the box it is DQ0Q1Q2Q3.

option is a) 3  b) 4 c) 6  d) 7  

Comments

c)

Answer 1

As per question we have arrangement as shown in fig .

We have arranged the registers are  Q0,Q1,Q2,Q3 input to Q0 is  ((Q2 ex-or Q3) Ex-Or Q0)

as per current values we have Q0,Q1,Q2,Q3 as 1000 now ,

                 

CLOCK NUMBER	Q0	Q1	Q2	Q3	INPUT At D (Q2 exor Q3 exor Q0)
its already loaded input	1	0	0	0	1
CLOCK 1	1	1	0	0	1
CLOCK 2	1	1	1	0	0
CLOCK 3	0	1	1	1	0
CLOCK 4	0	0	1	1	0
CLOCK 5	0	0	0	1	1
CLOCK 6	1	0	0	0	DESIRED OUTPUT GOT.

Hence in 6th clock we got output as 1000

Comments

thanks bro i got it.

---

SHUBHAM SHASTRI

how can you start with 1000? in question, order is Q3,Q2,Q1,Q0.

if you are taking order as Q0 Q1 Q2 Q3 you should start with 0001.

---

yes you are correct .. i  went wrong there

---

okay :)

Answer 2

This will be the sequence after each clock cycle:

0001(in order Q0, Q1, Q2, Q3)

1000

1100

1110

0111

0011

0001

1000

After 7th clock cycle, we will get 1000.

Comments

Utkarsh bro but the answer is 6th clock pulse..

---

how?

---

i dont know that why i post the question here.

---

Do you find any mistake in the solution?? If not consider 7 as the answer. their solution might be wrong.

---

but brother may be your solution wrong i think i should wait for some better answer then i go to final decesion.

---

@Utkarsh Joshi you are correct but why you are taking given condition as clock 1...

Means your clock 1 is already exsisting pattern , no need to count it .

 

---

@utkarsh joshi

1000 (Q3, Q2, Q1, Q0) this is given in question

now you have taken initialy

1000 (which is right)

means after doing exor opration of Q3,Q2,Q0 =1 ,you put this value at the the position of Q3 and shifted the remaining bits and you got 1100

but according to figure it should be put at Q0  position

---

I have considered 0001 initially. read carefully.