C Programming quiz

Question

Consider the following C-fragment:

#include<stdio.h>
int(*foo())[3]
{
  int a[3]={1,2,3};
  printf("%d",*a);
  return &a;
}
 
int main()
{
  int (*p)[3];
  p==foo();
  printf("%d",*(*p+2));
  return 0;
}

$A)13$        $B)10$        $C)31$        $D)Compilation$ $error$

Comments

p is a pointer to array ===> first de-reference lead to 1-D array, again de-referencing lead to element of the Array.

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.......

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it is not like

p = arr, it is like p=&arr

even though you write 100 in the value of p, but there is a difference between them,

it may helpful  https://gateoverflow.in/254355/test-series-question