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Answer is 81

Given that det(A-I)=0 and A, I are 3*3 matrix so there are 3 eigen values $\Lambda1,\Lambda2 and \Lambda3$

Trace(A) =13=($\Lambda1+ \Lambda2+\Lambda3$)

Det(A)=32=($\Lambda1*\Lambda2*\Lambda3$)

Now as det(A-$\Lambda$*I)=0

So $\Lambda$1=1

Substituting it in trace and det(A) we get other two eigen values as 8,4

=8^2+4^2+1^2

=81
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