In the given order find the value of h(k) for each given key, here 21 will give h(k)=21%10=1 as h(1) is empty place 21 there.
Similarly for each key and when there's a collision.As in que it's given as use Quadratic rehashing i.e. H+1^2,H+2^2,H+3^2 and so on this is done to resolve collision.
So for 30 as key 20 already exist in 10 so collision
H(30) =30%10 =0 (collision)
Rehash taking 1^2= (H(30)+1^2)%10=1(as collision occurs again take 2^2 in place of 1^2
=(H(30)+2^2)%10=0+4%10=4 (index 4 is empty so collision is resolved)
Proceed in similar way for others.
