as per my knowledge,
in the FD CD -> E, D is not redundant....
due to CD -> E only, C -> D happens via E ->A A -> B and B -> D.
what is the solution they provided?
@Shaik Masthan @tusharforever @srestha I have a doubt here.
CD ---> E , D is extraneous attribute only if C closure can generate D on removal of D?
I dont get this condition would you please elaborate?
My doubt is why in the FD CD -> E, D is not redundant....?
What do you mean by left side of each function is unique??