f∈O(g) = f≤c.g(n) g∈O(f) = g≤ c1f(n)
if we take same function for both f and g then a b and c can be possible for some constant.
a) f∈O(g) and g∈O(f)
b) f∈Θ(g) and g∈Θ(f)
c) f∈Ω(g) and g∈Ω(f)
d) f∈O(g) but g∉Ω(f)
f∈O(g) = f≤c.g(n) for some constant and it also implies that g∈Ω(f) coz for some constant g≤ c.f(n) is possible
so i think option D.