1 votes 1 votes I think percentage of processor time consumed should be $\frac{ \,ISR\,time}{ISR\,time+\,Data\,Transfer\,Time}=\frac{100}{100+122}$. Is it correct? CO and Architecture co-and-architecture interrupts io-handling numerical-answers + – Ayush Upadhyaya asked Oct 30, 2018 • retagged Aug 6, 2022 by Shubham Sharma 2 Ayush Upadhyaya 1.2k views answer comment Share Follow See 1 comment See all 1 1 comment reply Ayush Upadhyaya commented Nov 3, 2018 reply Follow Share Same:https://gateoverflow.in/65890/input-output 0 votes 0 votes Please log in or register to add a comment.
Best answer 3 votes 3 votes fraction of processor time = 100/122=81.96% it is correct Raghava45 answered Oct 30, 2018 • selected Nov 3, 2018 by Ayush Upadhyaya Raghava45 comment Share Follow See all 0 reply Please log in or register to add a comment.
