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lets say

P(x): x is a person

L(x,y): x loves y

so the above statement is ~(everyone who loves someone is loved by someone)

~∀x[ (P(x)∧∃y p(y)→L(x,y))  →  ∀z(P(z)∧L(z,x)) ]

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veer2000 asked May 6, 2023
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Prove or disprove (a) ∃x(P(x) ↔ Q(x)) → ¬∀xQ(x) ∨ ∃xP(x).