1 votes 1 votes radha gogia asked Nov 1, 2018 radha gogia 2.8k views answer comment Share Follow See all 6 Comments See all 6 6 Comments reply Show 3 previous comments Hemanth_13 commented Nov 1, 2018 reply Follow Share All the flipflops will operate at the same time. N-1th flipflops previous state o/p will be the input as current input to nth. So there won't be any delay. All will run in parallel 0 votes 0 votes radha gogia commented Nov 4, 2018 reply Follow Share I have just one doubt , say I have 3 FF ,Now output of 1st flip flop is connected to input of 2nd FF and output of 2nd FF is connected to input of 3rd FF . Now until we get op of 2nd FF , how can we get OP of 3rd FF , so we should take into consideration the delay of all flip flops . 0 votes 0 votes Hemanth_13 commented Nov 4, 2018 reply Follow Share Check this Link https://gateoverflow.in/260633/self-doubt 0 votes 0 votes Please log in or register to add a comment.
1 votes 1 votes Its synchronous counter so , Propagation delap = T(f-f)+ T(combinational) T(pdsyn) = 15 + 5 =20 ns F= 1/T(pdsyn) = 50 HZ shivam001 answered Nov 23, 2019 shivam001 comment Share Follow See 1 comment See all 1 1 comment reply jlimbasiya commented Jan 13, 2020 reply Follow Share So answer will be option A as we require min clock of 20ns . but clock time more than 20ns is allow but less is not allowed 0 votes 0 votes Please log in or register to add a comment.