Consider the following schedules:
S1: r1(A); r1(B); w1(C); w2(D); w1(A); w2(A); r1(D);
S2: r1(A); r1(B); r1(C); r1(D); w1(A); w2(B); w3(C); w4(D)
Which of the following option is correct?
A. S1 has blind writes and S2 is not
B. S2 has blind writes and S1 is not
C. Both schedules are conflict serializable
D. None of the above