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$\lambda = \text{ number of calls in 1 minute} = \frac{1}{5} = 0.20$

$P(X \geq x) = e^{ - \lambda x}$

$P(X < x) = 1 - e^{ - \lambda x}$

So,

$P(X<1) = 1 - e ^{-0.2 \times 1} =  0.18126$