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ACE TEST SERIES QUESTION
Shankar Kakde
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Nov 1, 2018
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Nov 1, 2018
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Mk Utkarsh
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Shankar Kakde
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Nov 1, 2018
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Mk Utkarsh
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Utkarsh Joshi
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Nov 1, 2018
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It follows exponential distribution with parameter 1/5. So, I guess 0.1638 is the correct answer.
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smsubham
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How to know it follows exponential distribution? I guess in GATE they will mention it.
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$\lambda = \text{ number of calls in 1 minute} = \frac{1}{5} = 0.20$
$P(X \geq x) = e^{ - \lambda x}$
$P(X < x) = 1 - e^{ - \lambda x}$
So,
$P(X<1) = 1 - e ^{-0.2 \times 1} = 0.18126$
Mk Utkarsh
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