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Original question link - https://gateoverflow.in/78987/packet-loss-numerical-in-stop-and-wait

 

I know this question has already been solved by Arjun Sir, but is there any other explanation which can simplify things?

 

In a communication link out of p packets one packet will be lost. If stop and wait protocol is used then expected number of retransmissions for a packet?

(A) P/(1-P)

(B) P

(C) 1/(1-P)

(D) 1/P

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