~~450/126=3.57 MBps?~~

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A leaky bucket with the capacity of 200 MB is at the host network interface.The data rate on the network is 2 Mbytes/s.If the host has 450 Mbytes to send onto the network and it sends the data in a burst then the maximum data speed from the host in order that no data is lost is_____ in Mbytes.(upto 1 decimal place)

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@magma

Please help me in understanding concept behind it.

What is the meaning it sends the data in burst?

How actual data (450/X) * 2 and how you have formed the equation?

Please suggest

Please help me in understanding concept behind it.

What is the meaning it sends the data in burst?

How actual data (450/X) * 2 and how you have formed the equation?

Please suggest

0

see brother

we used two bandwidth

one from senders to bucket and 2nd from bucket to network as per question

Now , let bandwidth of senders to bucket = X b/sec

we have data size = 450 MB

How much time is takes to transmit the data onto the link ?? = 450 / X sec

now in this (450 / X ) sec how much taka we're able to send to the network from the bucket ??? 2*450/X = 900/X MB right ?? Bucket to network bandwidth is given = 2MBPS

And that 450/X sec time how much data can we can send from sender to bucket = (450 / X) *X

now compute both of them

450 - 900/X = 200 {this is a overflow condition ... because if we send data from senders to bucket in greater bandwidth than the bucket to network...than we need 200 MB bucket capacity to store the data ...If we use less that 200 than there will be a case of overflow isn't it ?? }

we used two bandwidth

one from senders to bucket and 2nd from bucket to network as per question

Now , let bandwidth of senders to bucket = X b/sec

we have data size = 450 MB

How much time is takes to transmit the data onto the link ?? = 450 / X sec

now in this (450 / X ) sec how much taka we're able to send to the network from the bucket ??? 2*450/X = 900/X MB right ?? Bucket to network bandwidth is given = 2MBPS

And that 450/X sec time how much data can we can send from sender to bucket = (450 / X) *X

now compute both of them

450 - 900/X = 200 {this is a overflow condition ... because if we send data from senders to bucket in greater bandwidth than the bucket to network...than we need 200 MB bucket capacity to store the data ...If we use less that 200 than there will be a case of overflow isn't it ?? }

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Thanks @magma

Nicely explained :)

This question is from concept leaky bucket or token passing topic from tcp?

Nicely explained :)

This question is from concept leaky bucket or token passing topic from tcp?

0

now in this (450 / X ) sec how much taka we're able to send to the network from the bucket ??? 2*450/X = 900/X MB right ??

may be that statement might help you Utkarsh Joshi

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