+1 vote
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Fourier series of the periodic function (period 2π) defined by

$$f(x) = \begin{cases} 0, -p < x < 0\\x, 0 < x < p \end{cases} \text { is }\\ \frac{\pi}{4} + \Sigma \left [ \frac{1}{\pi n^2} \left(\cos n\pi - 1 \right) \cos nx - \frac{1}{n} \cos n\pi \sin nx \right ]$$

But putting $x = \pi$, we get the sum of the series

$$1 + \frac{1}{3^2} + \frac{1}{5^2} + \frac{1}{7^2} + \cdots \text { is }$$

1. $\frac{{\pi }^2 }{4}$
2. $\frac{{\pi }^2 }{6}$
3. $\frac{{\pi }^2 }{8}$
4. $\frac{{\pi }^2 }{12}$

asked in Calculus | 330 views

First of all, Fourier series of given function is calculated wrong here.

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