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In the circuit shown in figure, value of input P goes from 0 to 1 and that of Q goes from 1 to 0. Which output forms shown in figure represents the output under a static hazard condition?

asked in Digital Logic by Active (4.8k points)
edited by | 77 views
0
d??
0
Yes can you please explain
0
lets consider a case in which P change 0 to 1 before Q change 1 to 0 so at this instant both are 1

and given gate is and gate so result will be 1 at this instant of time
0
Not getting it
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wait 1 minute
0
d is correct option.

1 Answer

+3 votes

lets consider a case in which P change 0 to 1 before Q change 1 to 0 so at this instant both are 1 
and given gate is AND gate so result will be 1 because both input are 1 at this instant of time

theory resourse https://www.geeksforgeeks.org/digital-logic-static-hazards/ 

answered by Loyal (9.5k points)
+1
Got it thanks :)
0
It's not seems correct to me.
0

 kumar.dilip

tell me what is incorrect

0
What type of hazards is this ??
+1
@dilip

it is static 0 hazard

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