what is d answer? 5 or 7

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If the bandwidth of a medium is 100 Mbps and round-trip time is 50 microseconds then calculate the sequence bits in Go Back N ARQ flow control policy is applied and frame size 100 bits has to be transfer.

A ) 5

B) 6

C) 7

D) None of these

A ) 5

B) 6

C) 7

D) None of these

0

Anwer will be 6. We have 50 microsec and we have bandwidth 100 mbps. So,we can send 5000 bits in that round trip time. So,each frame cntains 100 bits so,5000/100=50 frames. So, for 50 frames we must have log(50)=6 sequence bits.

+1

how r u processing this question.

ws+wr<=ASN(AVAILABLE SEQUENCE NUMBER)

we have to find ws(sender window size)

capacity of channel/frame bits will give the same

ceil of log(ws+1) will give the answer

ws+wr<=ASN(AVAILABLE SEQUENCE NUMBER)

we have to find ws(sender window size)

capacity of channel/frame bits will give the same

ceil of log(ws+1) will give the answer

0

We can send 50 frames. So,window size =50. So,sequence number =window size+1.So 51. Taking ceil(log(51)) will give 6 as the answer.

0

thanks rahul

i am doing a mistake now problem has been solved

i am taking RTT as propagation time which is wrong

i am doing a mistake now problem has been solved

i am taking RTT as propagation time which is wrong

+1 vote

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