1 votes 1 votes Let X = X2X1X0 and Y= Y1Y0 be unsigned positive 3 digit and 2 digit numbers respectively. The output function 'f' = 1 only when X>Y otherwise '0'. Then the value of output f is equal to A. B. C. D. Digital Logic made-easy-test-series digital-logic number-representation + – Gupta731 asked Nov 9, 2018 edited Mar 4, 2019 by akash.dinkar12 Gupta731 1.1k views answer comment Share Follow See all 10 Comments See all 10 10 Comments reply Shubhgupta commented Nov 9, 2018 reply Follow Share Answer will be c. Make a kmap and put 1 where x is greater than y. after solving you will get c as max term. 0 votes 0 votes Gupta731 commented Nov 9, 2018 reply Follow Share There are 5 variables. how will I make a k map? 0 votes 0 votes Hemanth_13 commented Nov 9, 2018 reply Follow Share A?? x2x1x0==> 010=>2 y1y0===>01==>1 0 votes 0 votes Gupta731 commented Nov 9, 2018 reply Follow Share Answer is given C. 0 votes 0 votes Hemanth_13 commented Nov 9, 2018 reply Follow Share Sorry I haven't tested all the options yet :P 0 votes 0 votes Hemanth_13 commented Nov 9, 2018 reply Follow Share Yes taking 010 for X and 01 for Y will leave with one option i.e. C 0 votes 0 votes Gupta731 commented Nov 9, 2018 reply Follow Share Please explain the process properly 0 votes 0 votes Shubhgupta commented Nov 9, 2018 reply Follow Share as you know that when x2 will be 1 then in all 16 cases you will get x>y so make only for x1x0y1y0(for 4 varibale) and add x2 in each max term you will get your answer. 0 votes 0 votes Hemanth_13 commented Nov 9, 2018 reply Follow Share Take X2->0 X1->1 X0->0 Y1->0 y0->1 Option A. fails at second condition Option B fails at third condition Option D fails at second condition Option C gives 1 to all the conditions 0 votes 0 votes Deepak Poonia commented Oct 17, 2023 reply Follow Share Source: GATE IN 2019 Question 35 https://gate.iitk.ac.in/GATE2023/doc/papers/2019/in_2019.pdf Another Source: GATE IN 2007 Question 50 https://gate.iitk.ac.in/GATE2023/doc/papers/2007/in_2007.pdf 0 votes 0 votes Please log in or register to add a comment.