in Mathematical Logic edited by
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I am getting b) but right option is a) please check it 

in Mathematical Logic edited by
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There is no free lunch can be rewritten as "It is false that there is at least 1 free lunch".So a is true.

Statement b is the negation of the statement "Every lunch is free".In this negation, there can be some lunch which is not free.But the given statement is "There is no free lunch"
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amitqy shouldn'nt this line- there can be some lunch which is not free

is - (x)(Lunch(x)$\wedge$$\sim$Free(x))

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I understand it as : There exists at least one lunch and it is not free.
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